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4x^2-102x+594=0
a = 4; b = -102; c = +594;
Δ = b2-4ac
Δ = -1022-4·4·594
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{900}=30$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-102)-30}{2*4}=\frac{72}{8} =9 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-102)+30}{2*4}=\frac{132}{8} =16+1/2 $
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